x^2-4x-59=-28

Solution for x^2-4x-59=-28 equation:

x^2-4x-59=-28

We move all terms to the left:

x^2-4x-59-(-28)=0

We add all the numbers together, and all the variables

x^2-4x-31=0

a = 1; b = -4; c = -31;
Δ = b2-4ac
Δ = -42-4·1·(-31)
Δ = 140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{140}=\sqrt{4*35}=\sqrt{4}*\sqrt{35}=2\sqrt{35}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{35}}{2*1}=\frac{4-2\sqrt{35}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{35}}{2*1}=\frac{4+2\sqrt{35}}{2}
$